3 Phase AC Delta Current Question how was this answer obtained?

VulcanCCIT said:

For my education ... I understand vector 1 ... x=12 y=0 but can you explain or state the formula for vector 2?

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acos(0.80) = 36.86989765...° ;Phase Angle for Radio

So 20A ∠ 36.869897645844021296855612559093° = Vector 2 (Adjacent is 16, while Opposite is 12)

Final vector is 30.46309242 ∠ 23.19859051°

Multiplying the final vector current by 1.732 = 52.76207608A

Thanks to everyone for helping me catch my mistake.