50 years ago that would have been a good question.View attachment 119321 A schematic is attached for a C`E Voltage Amplifier Circuit.
Who ??According to Heath-Zenith
R1 and R2 have a strange low values but ok.his circuit was designed for a centered Q-point.
Component values are: R1 = 3.9K Ω, R2 = 1.5KΩ, Rc = 3.3KΩ, Re1 = 120Ω, RE2 = 1.5kΩ,
C1 = C2 = C3 = 47uF, Transistor = 2N3904.
Supply voltage = 20V
Gain = 10
Icq = 3 mA
Measured voltages are: Vc = 10.3V, Ve = 4.8V, Vb = 5.5V, Vceq = 5.4V.
Without the load resistance (RL) the minimum voltage at collector will be equal around 5.2VWhat would the maximum, undistorted ouput voltage be? Heath claims that it should be 4.42V.
I calculate around 5V (10V peak to peak); approximate voltages for Vc and Ve, 10V and 5V, respectively.What would the maximum, undistorted ouput voltage be? Heath claims that it should be 4.42V.
Referring to this Heath-Zenith course material that I have (I question it's quality). It
says that this circuit will have an output that rides on a Vc of 10.3 V. So that the max
undistorted output would be 10.3 + 4.4 = 14.7V peak and a minimum undistorted output
of 10.3-4.4 = 5.9V peak.
This is so confusing.
Regards,
John
Why do you allow ignorant jerks like Dodgydave to remain members of this site. People are trying to learn and we appreciateJony130 wrote:
Who?
Zenith, a consumer electronics company bought the struggling electronic kit maker Heath (as in Heath Kits) and went out of business soon after that.
If you do not watch your language and curb your temper you will be booted of this site pronto.Why do you allow ignorant jerks like Dodgydave and Jony130 remain members of this site. People are trying to learn and we appreciate
those that help us! We don't need the ignorance that some of these people are displaying!
This is what I calculated:It
says that this circuit will have an output that rides on a Vc of 10.3 V. So that the max
undistorted output would be 10.3 + 4.4 = 14.7V peak and a minimum undistorted output
of 10.3-4.4 = 5.9V peak.
This is so confusing.
If you do not watch your language and not curb your temper you will be booted of this site pronto.
Thanks Dennis.This is what I calculated:
View attachment 119328View attachment 119329
The output signal will be distorted when the positive portion approaches 20V or the negative portion causes the transistor to begin saturating.
While I agree with your sentiments, your attitude is a bit thick for someone with only 4 messages. I recommend that you focus on the responses that help, and ignore the ignorables. Basic transistor circuit theory never goes out of style, but an over-exaggerated view of one's place in the universe never is helpful.We don't need
Just because some people are long-time members, doesn't mean their behavior is appropriate/friendly.If you do not watch your language and curb your temper you will be booted of this site pronto.
john55 was permanently banned yesterday. You are headed for the same fate.No. You ban the jerks!