thatoneguy
- Joined Feb 19, 2009
- 6,359
Put a 1k resistor across where the motor would normally connect. Then read the voltage drop across it. Without a load, the high input impedance of a meter can show a voltage that is "parasitic", e.g. not able to actually source current.
You should be able to determine the current and direction then using Ohm's law with a resistor as the motor (drawing much less current).
The protection from shoot through is dead time to ensure one switch is off before turning the other one on. Adding a capacitor to the power supply only stabilizes the power, and would be discharged when the power rail is shorted.
The Relays will work, but only for forward/reverse, not PWM/speed control. If you read the datasheet linked above, most of your questions are answered within it.
You should be able to determine the current and direction then using Ohm's law with a resistor as the motor (drawing much less current).
The protection from shoot through is dead time to ensure one switch is off before turning the other one on. Adding a capacitor to the power supply only stabilizes the power, and would be discharged when the power rail is shorted.
The Relays will work, but only for forward/reverse, not PWM/speed control. If you read the datasheet linked above, most of your questions are answered within it.