That figure is fine (except it should be x=0 and not x' = 0)

You could also label it x and x'; but x=1 and x'=0 are the same thing (since x' means NOT(x)).

It sounds like you need to set this problem aside for a bit and make sure you know how to work with 5 and 6 variable K-maps.

 

That figure is fine (except it should be x=0 and not x' = 0)

You could also label it x and x'; but x=1 and x'=0 are the same thing (since x' means NOT(x)).

It sounds like you need to set this problem aside for a bit and make sure you know how to work with 5 and 6 variable K-maps.

Greetings
Yes...I took some time off to understand 5 Var K Maps
I've come up with the attached file instead of 3D....using what you suggested 5 var k map with 4x4 array
X bar = 0 & X=1. Now from what i have researched I understand...but in my case where I have
X bar = 0 and X = 1 When my next state variable A or S0 is 1 producing the same result I'm puzzled again
how i'll be representing test. ie INPUT 0 & 1 = 0100 for Next State S0 or A

 

Greetings
Yes...I took some time off to understand 5 Var K Maps
I've come up with the attached file instead of 3D....using what you suggested 5 var k map with 4x4 array
X bar = 0 & X=1.

You are still making the same mistake.

If I tell you that the inverse of the signal z is LO (i.e., z' = 0), you know that signal z must be HI (i.e., z = 1), right?

Well, that means that z' = 0 and z = 1 are the SAME THING!!!

For one map x = 0 and for the other map x = 1.

Or, equivalently, for one map x' = 1 and for the other map x = 1.

Do NOT mix them!

 

Alright...I believe what you were trying to say finally sank in...i only realized I labelled the K Map 0 - 31 when it should have been 0 - 15 also
which is why i was lost about what i said earlier...I think I have the correct thing now