https://www.dropbox.com/s/mb8xndx0xjzrskn/nnn.PNG

anyone help to know the steps and answer , sketch
for the question i thinks the answer is no the shape will not change




thanks in advanced

 

Well, sketch what you think the waveform will look like for the two input waveforms and then we will have something to discuss.

 

for Vin = 5V p-p , nothing is passing through the zener
At Vin= 10Vp-p, half sine wave ( negative part ) appears,

 

and the answer is no it won't change
is it right ???

 

Think about that. Let's just take your claims about the waveforms at face value.

Case 1: Nothing appears.

Case 2: A half-sine wave appears.

Claim: Case 1 and Case 2 have the same shape.

Do YOU buy that claim?

As for whether your claims about the two output waveforms is correct, you need to sketch what you think they will be. Then we can talk about specific things in your sketch that may or may not be correct in a meaningful way.

 

I change my answers i think it will be like this
https://www.dropbox.com/s/kijyto1u6px4aji/IMG-20140310-WA0000-1.jpg

the dead line is at 10:00

 

What will help you a lot is if you prepare a DC transfer characteristic. This is very simple and straightforward. On the horizontal axis you plot an input voltage -- in your case, make it go from -10V to +10V since that is the range you are interested in. On the horizontal axis you plot the corresponding output voltage.

The plot should consist of just a few straight line segments. Off the top of my head I think it should be three -- one for when the zener is forward-biased and conducting, one for when the zener is non-conducting, and one for when the zener is reverse-biased and conducting.

With that chart in hand, you can very readily plot the output waveform for an input waveform.