# wyedelta

Discussion in 'Homework Help' started by albn, Jul 6, 2012.

1. ### albn Thread Starter New Member

Jul 6, 2012
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0
what is the unbalanced current flowing in the neutral of this three-phase,four wire,208/120-volt system? A phase=52 amperes, B phase=44 amperes, C phase=46 amperes.

A. 7.21 amperes
B. 7.07 amperes
C. 7.34 amperes
D. 6.78 amperes

Please show the computation and thanks for any help and it's highly appreciated al_benigno@comcast.net

2. ### strantor AAC Fanatic!

Oct 3, 2010
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$\sqrt{(Ia^{2}+Ib^{2}+Ib^{2})-(Ia*Ib)-(Ib*Ic)-(Ia*Ic)}$

Last edited: Jul 6, 2012
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3. ### t_n_k AAC Fanatic!

Mar 6, 2009
5,448
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Why not simply

$I_n=I_a\angle{0^o}+I_b\angle{-120^o}+I_c\angle{-240^o}$

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4. ### albn Thread Starter New Member

Jul 6, 2012
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Hi! thanks for help I able to answer problems, more power to you

5. ### mlog Member

Feb 11, 2012
276
36
Now that makes sense.

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6. ### strantor AAC Fanatic!

Oct 3, 2010
5,032
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Sorry I don't know the masonic symbols. Not part of the club.

7. ### albn Thread Starter New Member

Jul 6, 2012
12
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Hi! guys thanks it's over the problems was solved and I really appreciate your inputs more power to you all.

8. ### amilton542 Active Member

Nov 13, 2010
496
64
I think T_N_K's defined the negative sequence set.