I am simulating a inverter design based on 4047 IC. The 220V ac output voltage graph is as shown, is this correct or typical type of waveform from such circuit?

 

No,
If your Circuit actually works, this "might-be" the expected Output with Zero-Load.
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with 1kohm load the graph looks like this:

 

It looks to me as though the transformer inductances are far too low.
But please, do us all a favour, and draw a proper circuit diagram, not one out of a kiddies' colouring book.

 

Hello,

You can not have any power, as R4 restricts the current dramaticaly.
Remove R4 and try again.

Bertus

 

Hello,

You can not have any power, as R4 restricts the current dramaticaly.
Remove R4 and try again.

Bertus

You beat me to it....

 

is this correct or typical type of waveform from such circuit?

It is not the correct waveform, which should be basically a square-wave.

 

What is the purpose of the 220Vac output?
For powering some electronic devices, a quasi-sinewave (stepped) output that has both the peak and RMS value of a sinewave may be better.

That can be generated from the CD4047 output with the addition of a CD4017 counter and a couple of OR gates (example circuit below using a 555 instead of a CD4047 to generate the clock. Note that the RMS value for the bottom composite trace is equal to that of a sine-wave with a 5V peak value).

 

What inductance did you use? Increase it by 100x. Then more and more.

 

I haven't simulated it, but I initially doubt that a a CD4047 can supply enough Current
to reliably and quickly switch the 1.5nF FET-Gates.

I think it would be a much better idea to simply spend the ~$20.oo for a Commercial-Inverter from Walmart.
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WHy would you want to use a 4047 when you can buy a SG2525?

 

I haven't simulated it, but I initially doubt that a a CD4047 can supply enough Current
to reliably and quickly switch the 1.5nF FET-Gates.

The 220 ohm gate resistors suggest they are switching at 60 or 100hz. Maybe it does not matter.

 

The 220 ohm gate resistors suggest they are switching at 60 or 100hz. Maybe it does not matter.

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Yeah, I get it,
but they should be switching at ~25kHz or more, and modulated by a Sine-Wave at 50 or 60Hz.
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they should be switching at ~25kHz or more, and modulated by a Sine-Wave at 50 or 60Hz.

Certainly if you want a true sine-wave inverter.
But the TS didn't state the purpose or use for the inverter.

 

They never do.
It's officially a given, almost an expectation.

 

See

 

See
View attachment 338066

whats the transformer primary and secondary inductances? I tried to use the software you used but its not running here because i am using windows 7.
thanks

 

whats the transformer primary and secondary inductances? I tried to use the software you used but its not running here because i am using windows 7.
thanks

In my circuit, the inductance of a winding with a large number of turns is 10H. The inductance of the windings L =w^2*AL. In this case, AL=10H/2000^2. Count it. In addition, the magnetic coupling coefficient is set. In a real transformer, the inductance can be even greater, as well as the magnetic coupling coefficient. Another transformer will require a different capacitor capacity. I'm sorry that you don't have Win10,11. Some managed to install Qspice on Win7. I didn't do it.

 

It looks to me as though the transformer inductances are far too low.
But please, do us all a favour, and draw a proper circuit diagram, not one out of a kiddies' colouring book.

I agree with Ian's analysis, the inductance is far to low for that transformer at 50Hz. If it could be resonated at 50 Hz with a suitable shunt capacitor it could look better.