A 2 k-ohm resistor is connected in series with a 4 k-ohm resistor and a 1.5 V battery of negligible
internal resistance. Calculate the voltages across the two resistors. Calculate the voltages
measured across the two resistors by a voltmeter with an internal resistance of 2k-ohm.?

 

Don't expect the solution. Show your work as someone can help you.

 

Here you go, get a-learnin'

http://www.allaboutcircuits.com/vol_1/chpt_6/2.html

 

i know what you want to say...!! i know voltage divider rule, but point is: when you measure voltage using voltmeter, you get the different answer. Just tell me the procedure how to figure it out. please show me the method, i know that there is internal resistance, but how does it come out different,mathematically.

 

The internal resistance of the voltmeter is calculated in parallel with the resistor which the voltage is measured across.

 

sir, kindly solve the numerical-problem that i posted, and please show me the method, that how would you get the answer.

 

You have three circuits here. First you solve circuit in Figure 1.

Then you solve the other two circuits.

 

thanx man...!!

 

A 2 k-ohm resistor is connected in series with a 4 k-ohm resistor and a 1.5 V battery of negligible
internal resistance. Calculate the voltages across the two resistors. Calculate the voltages
measured across the two resistors by a voltmeter with an internal resistance of 2k-ohm.?

I =1,5volts/6k
therefore voltage across 4k is 1.5volt*4k/6k and voltage across 2k is
1.5 volt*2k/6k the voltmeter should not have internal resistance of 2k unless this is a quiz