I seehi Z,
Tried that, removed R9.
LTSpice cannot solve the equations so goes into a continuous loop.
So no waveforms are created.
Why do you want to remove R9.?
E
Trying to understand
Can current flow from the source of the JFET to the drain?
I seehi Z,
Tried that, removed R9.
LTSpice cannot solve the equations so goes into a continuous loop.
So no waveforms are created.
Why do you want to remove R9.?
E
No, these diodes together with Zener diodes and R7 and R8 form the inverting Schmitt trigger.D1 and D2 is just for input protection?
Yes, it can. In this circuit, the JFET is working as a switch.Trying to understand
Can current flow from the source of the JFET to the drain?

ThanksNo, these diodes together with Zener diodes and R7 and R8 form the inverting Schmitt trigger.
Without these diodes, this Schmitt trigger cannot work. So you would have to use a traditional Schmitt trigger.
Yes, it can. In this circuit, the JFET is working as a switch.
When the voltage at A3 output is "Low" the JFET switch is "OFF" (open circuit, no current flow). On the other hand, when the voltage is "High" (A3 output) JFET switch is "ON" because the D5 diode is reverse biased thus JFET gate is pull-down via R10 resistor to GND so, JFET is "ON" (conducting current).
Also, notice that when the JFET is "ON" the current is equal to:
I_sd = 2*I_inV = 2*1V/20kΩ = 100μA. (if we ignore the JFET Rds_on)
Iin = Vin/20kΩ = 50μA
Thus the capacitor current is I_cap = I_sd - I_in = 50μA
View attachment 212058
Therefore the voltage at the A2 output will rise with the rate of I/C = 27.78mV/μs
So all you need to know to determine the output frequency equation it to know the Schmitt trigger threshold voltage.
It looks like the only purpose of R6 resistor is to limit the VDS so the JFET can work in triode region (ohmic region) or for safety reason (Vgd_max)Please what's use of R6?
It won't work. Try to calculate the threshold voltage in such a case when R1 = R2. And dos do not forget about the "phase" (inverting Vs non-inverting Schmitt trigger )Also, TS doesn't think the diodes and zener are necessary for operation. Can just do normal by using maybe 10k from output to "+" input and 10k from "+" input to ground
The JFET is a bidirectional device thus source and drain can be interchanged. And it will behave as a switch because JFET is "ON" when the Vgs = 0V and the actual drain current (Id) is smaller than the drain saturation current (Idss).Most importantly, please how JFET is operating as switch?
Though it is as analog switch when the signal is at the drain or source? confused
ThanksIt won't work. Try to calculate the threshold voltage in such a case when R1 = R2. And dos do not forget about the "phase" (inverting Vs non-inverting Schmitt trigger )
https://en.wikipedia.org/wiki/Schmitt_trigger#Inverting_Schmitt_trigger

Ah yes, with this configuration it will work. But I was thinking about this configuration (shorting the diodes)Really, it won't work?
Using 1k from output to '+' and 1k from '+' to ground (remove all the diodes)
like in the image
When output of A3 is 15V, "+" is 7.5V
when it is -15V "+" is -7.5V
Missing something?
How can a gate tell which terminal is a Source and which one is a Drain?Thanks
So dc current can flow from source to drain of NJfet?
HmmAh yes, with this configuration it will work. But I was thinking about this configuration (shorting the diodes)
https://en.wikipedia.org/wiki/Schmitt_trigger#/media/File:Op-Amp_Schmitt_Trigger.svg
How can a gate tell which terminal is a Source and which one is a Drain?
so please why is this not working?Ah yes, with this configuration it will work. But I was thinking about this configuration (shorting the diodes)
https://en.wikipedia.org/wiki/Schmitt_trigger#/media/File:Op-Amp_Schmitt_Trigger.svg
How can a gate tell which terminal is a Source and which one is a Drain?
Please why it's always on?This circuit does not work because your JFET switch is always "ON".
Here you have an example schematic with ideal switch.
View attachment 212128
You need a negative voltage with respect to the source to Turn OFF the N channel JFET.Please why it's always on?
The voltage at the gate doesn't determine this?
The solution shown in #29 is not enough?Please someone kindly make Spice in #28 work (when you can)
Is that JFET?The solution shown in #29 is not enough?
Try use a MOSFET instead for example 2N7000Is that JFET?