Using Relay to Power on Device

KeithWalker

Joined Jul 10, 2017
3,613
it may be able to supply up to 3A, but the circuit must negotiate the higher current.Unfortunately, I am not sure how to accomplish that.
Use a set of form-A contacts on the 34937A. Connect the +5V from the arduino to the C and the NO to the supply positive input to the speaker. Connect the Arduino GND to the supply negative input on the speaker. Power the Arduino through its USB connector from the USB-C port on your computer. When the contact closes, the speaker will be powered.
Of course, the speaker will need an audio input signal of some kind before it will do anything.
Keith
 
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djsfantasi

Joined Apr 11, 2010
9,237
Use a set of form-A contacts on the 34937A. Connect the +5V from the arduino to the C and the NO to the supply positive input to the speaker. Connect the Arduino GND to the supply negative input on the speaker. Power the Arduino through its USB connector from the USB-C port on your computer. When the contact closes, the speaker will be powered.
Of course, the speaker will need an audio input signal of some kind before it will do anything.
Keith
I thought the current requirements from the Arduino was 1.3A? This exceeds the Arduino capacity by a significant amount (it’s max is 400mA).

If the Arduino is only being used as a power supply, this is an extremely inefficient use of a uP. Direct from a USB connection may be possible, if it is USB C and the current can be successfully negotiated by circuitry.

Otherwise, this approach is a non-starter.
 

KeithWalker

Joined Jul 10, 2017
3,613
I thought the current requirements from the Arduino was 1.3A? This exceeds the Arduino capacity by a significant amount (it’s max is 400mA).

If the Arduino is only being used as a power supply, this is an extremely inefficient use of a uP. Direct from a USB connection may be possible, if it is USB C and the current can be successfully negotiated by circuitry.

Otherwise, this approach is a non-starter.
The USB-3 is supplying the current through the Arduino USB connector and out through the +5V pin. The available current is only limited by the USB source. The arduino is not actually doing anything other than giving access to the USB 5V supply.
 

KeithWalker

Joined Jul 10, 2017
3,613
The relays in the 34937A are actually not latching relays. They are turned on and off by the electronics. When a "close" command is received, a relay is powered on and remains powered by the electronics until an "open" command is received. That is why the manual refers to them as "latching".
It's all a matter of definition and interpretation.
I worked for HP/Agilent Technologies for 33 years.
Keith
 
yea. manuals are getting harder to read/understand now. I serviced HP stuff at work, mainly their x-y recoders and their power supply/amplifiers. The x-y recorders required regular service.

I know that when I was teaching someone anything, I first tried to figure out how they learned. Visual, verbal or kinestetic and then defined terminology. Some people were great in following recipes, but given a problem they could not solve it.

I could know very little about a piece of equipment and fix it with a trained operator. I knew what questions to ask.

I fixed some electronics like vacuum guages, High voltage power supplies, x-ray sets, RF transmitters, X-Y recorders, Scanning Electron Microscopes and switching power supplies.
 

Thread Starter

Andedam

Joined Jul 30, 2020
13
The Agilent 34937A does not contain any latching relays.
Hi again

So I thought about it, and will be switching the Arduino out with a Power Supply. From here on I can supply the device with directly 5 V through the relay, as well as I should be able to set the current to 1.3 A. That should do the trick, right? :)

Thanks in advance, BR Andedam
 

KeithWalker

Joined Jul 10, 2017
3,613
Hi again

So I thought about it, and will be switching the Arduino out with a Power Supply. From here on I can supply the device with directly 5 V through the relay, as well as I should be able to set the current to 1.3 A. That should do the trick, right? :)

Thanks in advance, BR Andedam
Using a 5V power supply would make much more sense if you have one. You don't need to adjust the current setting as long as it can supply at least 1.3A. The speaker will only take what current it needs. That will be nowhere close to the maximum except when it is outputting maximum sound.
Keith
 

KeithWalker

Joined Jul 10, 2017
3,613
yea. manuals are getting harder to read/understand now. I serviced HP stuff at work, mainly their x-y recoders and their power supply/amplifiers. The x-y recorders required regular service.
I remember those mechanically ingenious X/Y plotters and the power supply/amplifiers. That was a LONG time ago!
Keith
 
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