Use the rules of Boolean Algebra to show that

[B+A(C+D)]' = A'B' + B'C'D'

Thanks, could you also step me through it as am having difficulty working these ones out, i get very close but i seem to simplify it too far.

 

I did the following

B' + A'(C'+D')
B" + A'C' + A'D'
B'+ A'(C'+D')

but cannot work out how to make this equal the answer.

Thanks

 

use DeMogan's

=B' (AC)' (AD)' DeMogan's
=B'{(A'+C')(A'+D')}DeMogan'
=B'(A'+C'D')
=A'B'+A'C'D'

 

use DeMogan's

=B' (AC)' (AD)' DeMogan's
=B'{(A'+C')(A'+D')}DeMogan'
=B'(A'+C'D')
=A'B'+A'C'D'