When we bias a transistor in the active region using a single supply, and take the output across Vce , the ac waveform is riding on some DC, and so we use the coupling capacitor at the output.
In this site, i read in the section of the op-amp that the opamp uses a dual power supply (ie +15 and -15) so that the resulting output is pure AC, without any DC component. But i am not understanding how this is achieved.
Can you show how me this sort of method can be used to get a PURE ac in a BJT transistor amplifier, common emitter circuit, without the help of coupling capacitors..
In this site, i read in the section of the op-amp that the opamp uses a dual power supply (ie +15 and -15) so that the resulting output is pure AC, without any DC component. But i am not understanding how this is achieved.
Can you show how me this sort of method can be used to get a PURE ac in a BJT transistor amplifier, common emitter circuit, without the help of coupling capacitors..