Not necessarily. The DC voltage will have ripple on it. That is also likely affecting the OP's measurement.When measuring DC, WYSIWYG.
The voltage was taken without the cap, so the DC is only pulsed DC...so only god knows what the meter is reading.When measuring DC, WYSIWYG. Right? If 33V DC is read on the meter then I'm assuming it's seeing 33 volts. Of course when you add a load the voltage will drop because the load reacts in watts based on its resistance or reactance. When you draw current the voltage will drop. I'm fairly confident in that statement - but correct me if I'm wrong.
Not trying to hijack. More of a statement on my part that I don't fully know these things. My apologies if it seemed like I was trying to take over this thread.@ThePanMan please stop trying to hijack this thread, if you have questions please start your own thread.
No, not necessarily, if your meter reads 33VDC, it depends on how much ripple the DC voltage has. Across a capacitor with no load, the 33VDC is probably correct. However, if you have 10V ripple on an overloaded DC supply, that 33VDC may be an "average" reading as seen by the meter. The peak may be in fact higher.....
When measuring DC, WYSIWYG. Right? If 33V DC is read on the meter then I'm assuming it's seeing 33 volts.
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