Sorry in advance for the obtuse question. This is from a textbook example. While calculating the Thevenin Resistance for this circuit, they shorted the terminals a/b as expected. They then say, "observe that when the terminals a,b are shorted together, the control voltage v is reduced to zero..."
I see that the 25 Ohm resistor branch is shunted by this short and thus no current flows across it, but I guess I don't see why the voltage on the right-hand side (when shorted like this) would be zero throughout; whereas, when it's open (as in the photo), there is a voltage across a/b. I assume this is tied to why there's no current across ix when the a/b is open.
I see that the 25 Ohm resistor branch is shunted by this short and thus no current flows across it, but I guess I don't see why the voltage on the right-hand side (when shorted like this) would be zero throughout; whereas, when it's open (as in the photo), there is a voltage across a/b. I assume this is tied to why there's no current across ix when the a/b is open.
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