Summation problem

Thread Starter

Dritech

Joined Sep 21, 2011
907
Hi all,

Can someone please explain why the summation is equal to N, when infinity = 1 ?

I do understand that it is equal to 1^0 + 1^1 + 1^2 + ...... + 1?N-1 , but why is it equal to N?

Thanks in advance.
 

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shteii01

Joined Feb 19, 2010
4,644
Because it is math?

If N=1,
Then N-1=1-1=0,
Then Sum=1^0=1,
Therefore 1=1 and N=Sum

If N=2,
Then N-1=2-1=1
Then Sum=1^0+1^1=1+1=2,
Therefore 2=2 and N=Sum

If N=3,
Then N-1=3-1=2
Then Sum=1^0+1^1+1^2=1+1+1=3
Therefore 3=3 and N=Sum

There is one thing that is missing. There should have been a condition placed at the start of the excercise. This condition is: N>n (N is always gretater than n) or N-1=>n (N minus 1 is equal or greater than n).
 
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