Hello guys,

I wnat to take the square root of a complex over complex, i have set my calculator(casio fx-991ES plus)
to complex but when i try to calculate it gives me math error!!!! is there any set ups or its impossible to take square root of complex

 

Don't know about your particular calculator capabilities.
It's not that difficult a computation - if that's your main concern.
Starting with the original complex ratio value as a single value polar form, the square root is readily determined - as you presumably know. If your calculator can do the complex division and display the result in polar form the last step is relatively easy.
The polar form of the square root
\(\sqrt {A \angle {\pm \theta}} =\sqrt {A} \angle\pm \frac{\theta}{2}\)

 

Thanks it's easier now

 

Hi,

It might also help sometimes to remember:

sqrt(A/B)=sqrt(A)/sqrt(B)

 

Don't know about your particular calculator capabilities.
It's not that difficult a computation - if that's your main concern.
Starting with the original complex ratio value as a single value polar form, the square root is readily determined - as you presumably know. If your calculator can do the complex division and display the result in polar form the last step is relatively easy.
The polar form of the square root
\(\sqrt {A \angle {\pm \theta}} =\sqrt {A} \angle\pm \frac{\theta}{2}\)

In the square root you can add 2pi to theta ( one or more times ) before dividing the angle to get other square roots ( here just 2 in total)> More for cube roots, 4thf roots, etc.

 

Yeah it's called De Moivre's theorem.

 

http://www.wolframalpha.com/input/?i=(3+4i)^0.5

Why not use Wolfram Math ?

 

http://www.wolframalpha.com/input/?i=(3+4i)^0.5

Why not use Wolfram Math ?

Because some people want to actually learn the concepts behind the math instead of just letting a tool written by someone else do their thinking for them.