Put your 11R2 ohm resistor in a bucket of water ( 13.6 ohms would be better) for a reasonably
constant resistance. load.

I dont understand why this should be in a bucket of water

 

The thermal mass of a bucket of water and waters very high specific heat will help maintain the resistance at a steady temperature and consequently achieve a more stable resistance value that will not change so quickly due to heating.

 

The thermal mass of a bucket of water and waters very high specific heat will help maintain the resistance at a steady temperature and consequently achieve a more stable resistance value that will not change so quickly due to heating.

Thank you

The element so far has not even got warm

The best voltage we have had across the load since I started this is 2 Volts.

 

You will get a full sun, cloudless day soon.

When that coil of wire gets hit with a full 20 watts it WILL heat up.

 

Have you tried the short-circuit current, open-circuit voltage test?

 

Have you tried the short-circuit current, open-circuit voltage test?

I have not tried this test, how do I do it I am not sure

 

You hook the panel up to a current monitor or handheld multimeter.

You will be "shorting" the panel output through the meter.

A current meter contains a very very low value resistance through which the current is sent. By hooking it up between the two wires of the panel, the low resistance essentially shorts the panel and the maximum current the panel can produce at that illumination level will pass and can be read from the meter.

 

You hook the panel up to a current monitor or handheld multimeter.

You will be "shorting" the panel output through the meter.

A current meter contains a very very low value resistance through which the current is sent. By hooking it up between the two wires of the panel, the low resistance essentially shorts the panel and the maximum current the panel can produce at that illumination level will pass and can be read from the meter.

Thank you Very much

 

You hook the panel up to a current monitor or handheld multimeter.

You will be "shorting" the panel output through the meter.

A current meter contains a very very low value resistance through which the current is sent. By hooking it up between the two wires of the panel, the low resistance essentially shorts the panel and the maximum current the panel can produce at that illumination level will pass and can be read from the meter.

I hope I am getting this right. I have attached the graphs of the results that I have and a link to the weather that I was measuring in.

My results show a VERY low power output



https://www.dropbox.com/s/79myzhd17vkyj21/20 January Weather.mp4?dl=0

 

You may, in fact, have an electrical problem with your panel.
Was it new when you got it?

 

You may, in fact, have an electrical problem with your panel.
Was it new when you got it?

No it was not new, And the cables were shorted together when I got it.

I have a 10 Watt panel which I can use to experiment with

I will continue to use the 5R2 resistor