hai friends,

here(http://4.bp.blogspot.com/_Rde2-KfhfU8/TUWzOI-aElI/AAAAAAAAAs8/oBvIoj6kp6s/s1600/untitled.bmp) is the circuit I have small doubt regarding this circuit there two figures substitute fig B in fig A and find v(out)/v(in).

please help me

thanking you

 

What is your question? Where are you having trouble exactly?

 

hi, my question is substitute fig B in fig A and find Vout/Vin

 

friends please solve this

 

First of all, we won't do your homework for you. You have to make an initial effort to approach the solution, and we can help you after you are stuck. So post your work and we will comment on it.

 

here by applying nodal or mesh analysis

I observed that no current flows to the second loop..

then how the second loop will be activated....

note:here 5V is the dependent source

thanking you

 

Its a simple network. Let the BD line be the reference node.
First mark the two ends(+ve and -ve ends) of the voltage V as V1 and V2.
Find V1 in terms of Vin by applying voltage-divider rule.
Then find V2 in terms of V.
V=V1-V2 and find V in terms of Vin
Then find Vout.
If you still don't understand then I'll post the pic of solution.

There are other ways to solve the prob using 2 port analysis. But to start with my above solution will do.

thanking you

No need to mention. Its implicit when you ask the question

 

how to find v2 interms of v

 

Simple voltage=current*resistance. current=5V resistance=r3+r4
V2=5V(R3+R4)

 

sorry 5v is voltage not current

 

The output of the first potential divider is equal to the sum of the controlling potential V, and the dependant source voltage "5V".

The input to the second divider is the controlled voltage source "5V". How is that expressed as a fraction of the output of the first divider?

 

http://forum.allaboutcircuits.com/newreply.php?do=newreply&p=326936

sorry 5v is voltage not current
http://forum.allaboutcircuits.com/newreply.php?do=newreply&p=326936

http://forum.allaboutcircuits.com/newreply.php?do=newreply&p=326936
Well the diagram says its current source. Either the question is incorrect or the 5V is the voltage dependent current source.
If its the latter then the problem has a solution(which I have already suggested).

 

Well the diagram says its current source. Either the question is incorrect or the 5V is the voltage dependent current source.
If its the latter then the problem has a solution(which I have already suggested).

Right enough. The symbol on the diagram is for a current source ( the label "5V" means "5 times V", and does not tell you that its output is a voltage ).

If the diagram is right my earlier post was nonsense. The problem is soluble in both cases, but you need to know which.

@ veerendra: Can you confirm what the problem was really about?