i. Simplify the following Boolean equations.
ii. Sketch a reasonably simple combinational circuit implementing the simplified equation.
iii. Compare the numbers of literals and operators versus the numbers of gates, nets, and pins in the schematic diagrams
A. a′bc′ + a′b′d + a′b′cd′ + bc′d + acd + abcd′ + ac′d
So far, I have gotten this. Does this seem correct? I am unsure how to sketch the circuit...can someone please help with this?
i.
= a’bc’(d + d’) + a’b’(c + c’)d + a’b’cd’ + (a + a’)bc’d + a(b + b’)cd + abcd’ + a(b + b’)c’d
= a’bc’d + a’bc’d’ + a’b’cd + a’b’c’d + a’b’cd’ + abc’d + a’bc’d + abcd + ab’cd + abcd’ + abc’d + ab’c’d
= a’bc’d + a’bc’d’ + a’b’cd + a’b’c’d + a’b’cd’ + abc’d + abcd + ab’cd + abcd’ + ab’c’d
ii. Sketch a reasonably simple combinational circuit implementing the simplified equation.
iii. Compare the numbers of literals and operators versus the numbers of gates, nets, and pins in the schematic diagrams
A. a′bc′ + a′b′d + a′b′cd′ + bc′d + acd + abcd′ + ac′d
So far, I have gotten this. Does this seem correct? I am unsure how to sketch the circuit...can someone please help with this?
i.
= a’bc’(d + d’) + a’b’(c + c’)d + a’b’cd’ + (a + a’)bc’d + a(b + b’)cd + abcd’ + a(b + b’)c’d
= a’bc’d + a’bc’d’ + a’b’cd + a’b’c’d + a’b’cd’ + abc’d + a’bc’d + abcd + ab’cd + abcd’ + abc’d + ab’c’d
= a’bc’d + a’bc’d’ + a’b’cd + a’b’c’d + a’b’cd’ + abc’d + abcd + ab’cd + abcd’ + ab’c’d