This one-port network is given and I have to find the equivalent resistance in it.
I already have the answer for it but I'm still not quite understanding something about it.
My first attempt at this was:
300//200 + 400//100 = 120 + 80 = 200Ω
It seemed to me that the 300 was in parallel with the 200 resistor, and that was in series with a 400//100 resistor. But I realise why this is not the case.
I don't know anymore. Someone enlightened me today it was 100//400 in series with 200, in parallel with 300: (100//400 + 200)//300, which got the right answer.
I guess, can someone just explain to me how I can interpret stuff like this and what I should know/understand to avoid getting it wrong in the future?
Thanks.
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Offtopic, but is it me, or is the forums loading really slowly?
I already have the answer for it but I'm still not quite understanding something about it.
My first attempt at this was:
300//200 + 400//100 = 120 + 80 = 200Ω
It seemed to me that the 300 was in parallel with the 200 resistor, and that was in series with a 400//100 resistor. But I realise why this is not the case.
I don't know anymore. Someone enlightened me today it was 100//400 in series with 200, in parallel with 300: (100//400 + 200)//300, which got the right answer.
I guess, can someone just explain to me how I can interpret stuff like this and what I should know/understand to avoid getting it wrong in the future?
Thanks.
-------
Offtopic, but is it me, or is the forums loading really slowly?