Hello there.

Please see the code I have written below

void main(void)
{
int a[MAX];
int i, count=0;
printf("Enter vectors. Enter 666 to stop.\n\n");
for(i=0;i<MAX;i++)
{
printf("Vector %i: ", i+1);
scanf("%i", &a);
count++;
if(a == 666)
{count--;break;}

}

I am attempting to input an array of integers, and stop entering those integers either with a blank line, or a word. Anything but 666! It's so tacky.

I have tried %s in scanf and typecasting to an int, but that still does not terminate the loop when I substitute 666 for "stop" in the if statement.

I'm sure it's something simple, any suggestions?

Thanks,
Fraser

 

Wow console!


Been years since I have done all that much with it.


There are tons onf ways to do this but this is one:

// TestPrj.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <string.h>
#include <stdlib.h>


#define MAX 10

void main(void)
{
int a[MAX];
int i, count=0;
char str[1000];

printf("Enter vectors. Enter end to stop.\n\n");
for(i=0;i<MAX;i++)
{
printf("Vector %i: ", i+1);

scanf("%s", str);

count++;

if (strncmp(str,"end",3) == 0)
break;
else
a = atoi(str);




}


for (i=0; i<count-1; i++)
{

printf("Vector %i = %i: \n", i,a);


}
}


If I remember correctly you can also trap control break but I have not done that in years.


BTW Most of the functions above have been deprecated. Note sure what compiler you were using.

 

Hi there. I looked into the atoi function as it was new to me, set up an array for a temporary string as you suggested, tried atoi and it worked first time. much obliged!