Hey guys.
This should actually be an easy one.
Im playing with a PLD 5000 laser driver. Adding a diode to my cnc machine. It has a current monitor pin, as in you can read the outputgoing
Anyways, it says, in order to set the current from a voltage reading, use the transfer function:
V=I(LD) /2A/V
I(LD) is Current of LaserDiode.
My driving voltage is 12V. I'd l ike to hit around 1.5A
Am i correct in guessing that 2(1.5)/12 = 0.25=V?
Ie that if i read V=0.25 on my monitor pins, Im at 1.5Amps on the output?
This should actually be an easy one.
Im playing with a PLD 5000 laser driver. Adding a diode to my cnc machine. It has a current monitor pin, as in you can read the outputgoing
Anyways, it says, in order to set the current from a voltage reading, use the transfer function:
V=I(LD) /2A/V
I(LD) is Current of LaserDiode.
My driving voltage is 12V. I'd l ike to hit around 1.5A
Am i correct in guessing that 2(1.5)/12 = 0.25=V?
Ie that if i read V=0.25 on my monitor pins, Im at 1.5Amps on the output?