well I am not very familiar with this type of voltage regulator at all, so I did a quick google search and came up with the following

the following is an excerpt from this PDF http://www-personal.engin.umd.umich.edu/~fmeral/ELECTRONICS%20I/0300%20Linear%20Volt-Reg/0300%20Linear%20Volt-Reg.pdfpersonal.engin.umd.umich.edu/~fmeral/ELECTRONICS%20I
/0300%20Linear%20Volt-Reg/0300%20Linear%20Volt-Reg.pdf

Based on the first paragraph there I would need to load current to find Vout. correct?

 

The key elements are the zener diode voltage and the values of R2 & R3.

R2 & R3 form a voltage divider across the output. The LM741 op-amp will attempt to control the output such that the R2 + R3 divider output voltage fed back to the LM741 negative input is the same as the zener voltage.

 

ahhhh i see

Vout/Vin = R3/(R2+R3)
Vin=10V

 

ahhhh i see

Vout/Vin = R2/(R1+R2)
Vin=10V

That makes no sense when looking at your schematic.

 

That makes no sense when looking at your schematic.

sorry i was reading that formula off my paper where I had it translated for R1 and R2

it should be
Vout/Vin = R3/(R2+R3)

 

sorry i was reading that formula off my paper where I had it translated for R1 and R2

it should be
Vout/Vin = R3/(R2+R3)

You came up with Vin=10V. Which node is Vin?

 

i guess you could call it the top of R2.

between R2 and R3 is 5.6V

the bottom of R3 is GND

is this not correct?

 

i guess you could call it the top of R2.

between R2 and R3 is 5.6V

the bottom of R3 is GND

is this not correct?

I think you have figured it out. I just thought it would make more sense if you called the junction of R2 and R3 Vin, and the top of R2 Vout, since that's how it's labeled on the schematic.
If you do that, Vout/Vin=(R2+R3)/R3.
If you want to communicate using schematics, it is helpful if you stick to the labeling and reference designators on the schematic.