also, can someone explain or direct me into understanding bool identities, I need to prove that xz = ( x + y ) ( x+y' ) ( x' + z )
so I did the truth table as follows:
XZ =
X Z X&Z
0 0 0
0 1 0
1 0 0
1 1 1
and ( x + y ) ( x+y' ) ( x' + z ) as follows:
0 | 0 | 0 | 0 0 1 1 0
0 | 0 | 1 | 0 0 1 1 0
0 | 1 | 0 | 1 0 0 0 0
0 | 1 | 1 | 1 0 0 0 0
1 | 0 | 0 | 1 1 1 1 0
1 | 0 | 1 | 1 1 1 1 1
1 | 1 | 0 | 1 1 1 0 0
1 | 1 | 1 | 1 1 1 0 1
is that correct?
Also the identities are as follows:
XX+XX+YX+YY+YZ+XX+XZ+YX+YZ ;Distributive
XX+(XX)+YX+(YY)+YZ+(XX)+XZ+YX+YZ ; Associative
XX+YX+YZ+XZ+YX+YZ ; Inverse
and I'm stuck. Can anyone direct me to teach me how to do this... I read alot of articles but I dont understand much for it. Thanks!
so I did the truth table as follows:
XZ =
X Z X&Z
0 0 0
0 1 0
1 0 0
1 1 1
and ( x + y ) ( x+y' ) ( x' + z ) as follows:
0 | 0 | 0 | 0 0 1 1 0
0 | 0 | 1 | 0 0 1 1 0
0 | 1 | 0 | 1 0 0 0 0
0 | 1 | 1 | 1 0 0 0 0
1 | 0 | 0 | 1 1 1 1 0
1 | 0 | 1 | 1 1 1 1 1
1 | 1 | 0 | 1 1 1 0 0
1 | 1 | 1 | 1 1 1 0 1
is that correct?
Also the identities are as follows:
XX+XX+YX+YY+YZ+XX+XZ+YX+YZ ;Distributive
XX+(XX)+YX+(YY)+YZ+(XX)+XZ+YX+YZ ; Associative
XX+YX+YZ+XZ+YX+YZ ; Inverse
and I'm stuck. Can anyone direct me to teach me how to do this... I read alot of articles but I dont understand much for it. Thanks!