I'm saying that I'm trying to calculate Vout rms and Vout DC with those formulas but my results are not matching LTSpice's results.

Only for the half-wave rectification my calcs are close to LTSpice's results.

 

Have you allowed for the effect due to the diodes reducing the conduction time when calculating the Integrals for the RMS values.

I make it approx 9.25mSec compared to a 10mSec half cycle.

Please post the values you measure from the Plot and also your calculated values.

 

Have you allowed for the effect due to the diodes reducing the conduction time when calculating the Integrals for the RMS values.

I make it approx 9.25mSec compared to a 10mSec half cycle.

Please post the values you measure from the Plot and also your calculated values.

Looks like the problem might (now, I'm sure it is) be in the period time that decreases a bit depending on which setup we are using... I didn't knew about that fact and I'll recalculate everything again today!

 

With a full wave bridge allow for two Vfwd diode voltage drops..

 

With a full wave bridge allow for two Vfwd diode voltage drops..

But only for the Bridge setup, right? The center tap setup is only one Vfwd diode drop, right?

 

Yes, thats correct.
Post your calculations when ready.

 

What are the formulas to calculate, via integrals, the Vout DC???

I know that for RMS in half-wave, the formula has 1/T and on full-wave rectifiers, we have 2/T. But for DC calcualtion, is the same or is it different???

 

For Half-Wave Rectifier I used the following and results look close enough to LTSpice's!








But I can't do the same for Full-Wave Rectifiers even narrowing the conduction time of the diode!

 

Well I think that if we take into account a diode voltage drop and conduction time we can find V_out_average for Full-Wave Rectifier is

I assume Vf = 0.7V

And for Half-Wave Rectifier