Need help please
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yes and if its wrong help me figure it out please...So you just want people to vote on whether your answer is correct? Okay.
We can't help you figure out what you did wrong unless you show us what you did.my bad its 1/20 so the answer would be 9.7467
Sir Correct me if i'm wrongYou're at least closer.
How much total energy would be dumped into a 1 Ω resistor over the course of the waveform?
What is the average power being dumped into at 1 Ω resistor?
What DC voltage would dump that same average power into that same 1 Ω resistor?
This would be true only if Vrms = 9.7467 V, and it doesn't. You can't just assume that your answer is correct when the goal is to determine that your answer is correct.Sir Correct me if i'm wrong
power being dumped is p=v^2/r p=(9.7467)^2/1kiloohm
Don't cram everything together, the equation "v=sqrt1/Tintegral(v)^2dt" is almost unreadable.9.7467 Dc voltage would dump the same power
I figured out the rms value to find dc equivalent voltage as average of ac is zero so i take the Rms by formula v=sqrt1/Tintegral(v)^2dt
Agreed. Suggesting that he use a specific resistor value was just intended to make the concepts extremely concrete. But the concept is that it works for ANY resistor value (including a nonspecified symbol resistance R) and you can easily show that there is no need to even use that. It all falls out from the definition of "effective" power (not even "rms" power  the "rms" is a direct consequence of the definition of "effective" power).So I wondered if it would work for a 1Ω resistor, would it also work for a 33Ω resistor? And indeed it does, but it would still be simpler to calculate the RMS voltage as ½√350.
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