I have an electronics math problem that is driving me nutz.

10vAC in series with a 10k resistor, a .5mH coil, and a 560pF capacitor. Question is what is the resonance frequency?

Answer: 301 KHz

Problem:
1
---------------------------------
Fr = 2Pi * square root(.5 mH * 560 pF)


I get (9.5 kH) do you have an idea what step I’m missing?

 

Originally posted by VALKETEER@Mar 14 2006, 12:24 PM
I have an electronics math problem that is driving me nutz.

10vAC in series with a 10k resistor, a .5mH coil, and a 560pF capacitor. Question is what is the resonance frequency?

Answer: 301 KHz

Problem:
1
---------------------------------
Fr = 2Pi * square root(.5 mH * 560 pF)
I get (9.5 kH) do you have an idea what step I’m missing?

[post=14976]Quoted post[/post]​

I don't know where you went wrong, but here is my solution
0.5 mH = 0.5e-3 Henry, and 560 pF = 560e-12 Farad

Compute the denominator
2 * pi * √ (0.5e-3 * 560e-12) =
6.28 * √ (280e-15) =
6.28 * 529e-9 =
3.324e-6 and
Take the reciprocal
1 / 3.324e-6 = 300.77e3 =
301 kHz

 

Thanks, I see where I went wrong now.

 

Originally posted by VALKETEER@Mar 14 2006, 11:24 AM
I have an electronics math problem that is driving me nutz.

10vAC in series with a 10k resistor, a .5mH coil, and a 560pF capacitor. Question is what is the resonance frequency?

Answer: 301 KHz

Problem:
1
---------------------------------
Fr = 2Pi * square root(.5 mH * 560 pF)
I get (9.5 kH) do you have an idea what step I’m missing?

[post=14976]Quoted post[/post]​

When I run the numbers through your expresssion, I get 300,774 Hz.

hgmjr