Hi,
Everyone!
I have a question about a coupler division. I know that this type(quadrature hybrid coupler) has a power division ratio which is half to every output port but how can I make it so the ratio is 2 to 1 and the impedance's value is unknown. Thanks in advance.

 

Unclear what you are asking. 2:1 ratio of what? Impedance is unknown?

 

Unclear what you are asking. 2:1 ratio of what? Impedance is unknown?

The power division ratio at port 2 and 3 is “2:1”

 

The power division ratio at port 2 and 3 is “2:1”

It is already 2:1. Or did you mean between port 2 and 3, as in quadrature outputs but with unequal power split? In any case, you need to know the impedance you are working with.

https://www.microwaves101.com/encyclopedias/unequal-split-branchline-coupler

 

It is already 2:1. Or did you mean between port 2 and 3, as in quadrature outputs but with unequal power split? In any case, you need to know the impedance you are working with.

https://www.microwaves101.com/encyclopedias/unequal-split-branchline-coupler

Yes, between port 2 and 3 the power split should be 2:1. I know that the ration in a quadrature outputs should be equal but the problem requires a ration and Zo is unknown.

 

Hello,
everyone!
I am a student and I was wondering how can I make a two step 90° Hybrid Coupler that divides the output signal at ports 2 and 3 "2 to 1", because my assignment is to do a "90° Hybrid Coupler that divides the output signal at ports 2 and 3, 2 to 1".I know that the characteristics of a 90° Hybrid Coupler is that they divide the power signal in half. So how can I solve this problem. Looking forward to your suggestions.