It states:

"A bowl contains 3 red, 4 blue, and 5 green chips. If 3 chips are simultaneously drawn at random, what is the probability that all 3 chips are the same color? What is the probability that exactly 2 chips are the same color?"

Here is what I worked:

P(3 red) = 3/12 *2/11 *1/10

At first there are 3 red chips, then if one is removed, there are 2, and only 11 chips, and then only 1 red chip and 10 total chips

P(3 green) = 4/12 *3/11 *2/10

(Then similalry for green and blue)

P(3 blue) = 5/12 *4/11 *3/10

Well this method gives 3 answers, but does the question want just one answer? Would I multiply the three probabilities?

P(2 red) = 3/12 *2/11 *9/10

There are 3 red chips to choose, then removing 1 that leaves 2 chips out of 11, but then there are 10 chips, with 9 that are not red, so the probability of not picking another red is 9/10

P(2 green) = 4/12 *3/11 *8/10

Likewise probabilities for green and blue were found

P(2 blue) = 5/12 *4/11 *7/10

Again is this asking for one answer or are there the three answers actually?