Tmr2Setting EQU B'00000111' ;Timer2:no postscale,Timer2 on,/16 prescale
CCP1Setting EQU B'00001111' ;CCP1WM mode only 8 significant bits
PWMPeriod EQU 0xFF

Setup MOVLW PWMPeriod
MOVWF PR2 ;Set PWM period
BCF STATUS,RP0 ;Set bank 0.
MOVLW Tmr2Setting
MOVWF T2CON ;Set up Timer2 for PWM
MOVLW CCP1Setting
MOVWF CCP1CON ;Set up CCP1 for PWM
MOVLW 0xFF
MOVWF CCPR1L ;Setinitial PWM Duty cycle


PWM_Out ;PROCEDUREPWM_Out
MOVF Output,W
MOVWF CCPR1L
RETURN ;END PROCEDURE


came up something with this..with my values..is it oki?

 

i havent tested it out yet...i am still stuck with this values..my supervisor it doesnt matter if my PWm frequency is low..he just needs to see first my program and calculations.

i didnt get what you meant by " (100<< 2)".

electronics is really hard !

It is a left shift operation.... denoting shifting left twice.

For the third time, do you have an output waveform? If so, what is your program and ouput characteristics...

 

according according to the program i will have an output waveform.

from my earlier calculations :

my PWM period will be 2.048ms
my PWM frequency will be 488HZ

 

according according to the program i will have an output waveform.

I am not asking about what you might expect, I am asking what it is when you program the device and monitor its output using an oscilloscope.

 

i will get a waveform of 9.78% dutycycle.

*on the hardware part....i have yet not tested it*

i am sincerely not understanding this concept

 

i will get a waveform of 9.78% dutycycle.

*on the hardware part....i have yet not tested it*

i am sincerely not understanding this concept

So, you are simulating it, then? This is like pulling teeth! You need to tell me what you have!

 

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1)servo motor
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4).NET library

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