I know this about this problem so far two waves one is sine and other is cosine wave we have to find the sum so V=v1+v2 v1 is a sine wave and has amplitude of 10 so i got the amplitude and they have given me the time period 2ms from here i can get frequency = 2π/T = 2π/2 = π in the second one its a cosine wave so again amplitude 10 and frequency is same but the the phase difference is 90 degree what angle does sine have it starts at zero so its angle is 0 ? and cosine 90 and after this
v1(t)=10sin(wt+θ)
v2(t)=10cost(wt+θ)
v1(t)=10sin(wt+θ)
v2(t)=10cost(wt+θ)
Attachments

8.2 KB Views: 9