I'm going over my physics 2 final review and there is one problem that I think I know how to get but my professor tells me its done a completely different way..
So.. it says two capacitors of capacitance C1= 1.5 uF and C2= .5 uF are connected to an 8 V battery as shown in the figure above. Initially both capacitors are uncharged
A) When the switch S is turned to position 1, the plates of the capacitor C1 acquire a potential difference Vo. The switch is then turned to position 2. what are the final charges q1 and q2 on the corresponding capacitors?
Q1=3 uC, Q2=3 uC (since they're in series they have to have the same charge)
B) What is the potential difference across C2?
Vc1=2V, Vc2= 6V
So.. the thing I did was use Qeq=CeqV to find the equivalent charge (because both C1 and C2 shoudl have the same charge since the'yre connected in series).
My professor told me that C1 and C2 are in parallel once the switch is thrown to position 2 which I strongly disagree with.. I'm also taking circuits right now and everything we've learned in circuits completely contradicts that simple diagram being in parallel since they dont share any nodes (connecting 3 or more elements)..
So even after he told me they were in parallel, if all 8 V goes to C1 when the switch is in position 1, How did he get that C1 and C2 each have 6V? I understand if they were in parallel theyd have the same voltage but why would it be reduced to 6 V each?
Can someone please help me out with this discrepancy asap because my final is tomorrow and I just want to be prepared for the test:-/ Thank you!
So.. it says two capacitors of capacitance C1= 1.5 uF and C2= .5 uF are connected to an 8 V battery as shown in the figure above. Initially both capacitors are uncharged
A) When the switch S is turned to position 1, the plates of the capacitor C1 acquire a potential difference Vo. The switch is then turned to position 2. what are the final charges q1 and q2 on the corresponding capacitors?
Q1=3 uC, Q2=3 uC (since they're in series they have to have the same charge)
B) What is the potential difference across C2?
Vc1=2V, Vc2= 6V
So.. the thing I did was use Qeq=CeqV to find the equivalent charge (because both C1 and C2 shoudl have the same charge since the'yre connected in series).
My professor told me that C1 and C2 are in parallel once the switch is thrown to position 2 which I strongly disagree with.. I'm also taking circuits right now and everything we've learned in circuits completely contradicts that simple diagram being in parallel since they dont share any nodes (connecting 3 or more elements)..
So even after he told me they were in parallel, if all 8 V goes to C1 when the switch is in position 1, How did he get that C1 and C2 each have 6V? I understand if they were in parallel theyd have the same voltage but why would it be reduced to 6 V each?
Can someone please help me out with this discrepancy asap because my final is tomorrow and I just want to be prepared for the test:-/ Thank you!