I am stuck on another question that asks me to find the missing resistor of AB in the attached diagram. I know the following : R1= 30 ohms R2= 40 ohms R3 = 10 ohms R4= 10 ohms R5=60 ohms Now i know the formulas for calculating the R value for parallel and series circuits but can't figure it ou. I tryed seperating the circuits in smaller circuits . I did R2 & R5 as parallel and do i do series as R1 , R3 and R4 ? Thanks !
This makes no sense. Think about it. If I connect up those five resistors according to the diagram provided, how could you possibly tell that there even IS a resistor that is missing between A and B, let alone what value it is? You are missing some piece of information that gives the resistance between some pair of points in the circuit that involves the missing resistor.
Your right, but that is the only info i see. I found it wierd that there is no voltage or amps indicated anywhere in the circuit.
Anyway, according to my study sheet the answer is 33.33 ohms Not sure how they get it, but thats all the info i have.
They are not asking for the value of some missing resistor between A and B. They are asking for the equivalent resistance of THOSE resistors as seen between A and B.
That looks like Thevenin equivalent resistance problem. Just to clarify. Is English your native tongue?
It is probably asking what you is the (equivalent) resistance between A and B. Fairly easy once you redraw the picture.
I think i figured this one out thanks to ABSF new diagram. I found the total resitance of R2, R5 and R1 which is 13.33 ohms Then added in R3 and R4 for 33.33 Ohms Just re-drawing the schematic, i don't get why R1 goes in parallel when its in series in original diagram. Cause R2 and R5 are in parallel which in turn is in R1.
Two resistors are in series if they are the only two resistors on a given node. Two resistors are in parallel if both ends are connected to the same nodes. Identify the nodes. A simply way to do that is to color them. R1 is connected to the red node and the greed node, thus it is in parallel with any other resistor connected to the red node and the green node. The resistors on the green node are R1, R2, R3, and R5. Of these, R1, R2, and R5 are also connected to the red node. Thus R1, R2, and R5 are all in parallel.
You see thats my problem its hard for me to tell if a resistor is in series or parallel. The original diagram , it looks like R1 is in series.
Thanks Wbahn I appreciate you taking your time to point that out for me . You learn something new everyday !
Remember the definition of series. To be in series, whatever current flows in one MUST flow in the other. That means that whatever current flows out of one has to have no choice but to enter the other. Look at that green node and imagine a current flowing up out of R1. Does it HAVE to flow into R2? No, there is another path it could take. Similarly, consider current coming up out of the supply. Does the current then goes through R1 have to also go through R2? No. In order for the current flowing out of one to have to flow into the other, there must be no other paths available. If the two resistors are connected directly together at a certain node, this means that there must be no other devices connected to that same node.
ok i get it so basically all those resistors in that diagram are in parallel R1 R2 R3 R4 are all parallel
What are the color of the nodes connected to R3? What are the color of the nodes connected to R1? Can they be in parallel?