I was going to post this question on the original thread, but then I thought that maybe it deserves a thread of its own... and besides, I ain't no hijacker...The main reason to keep the frequency as low as possible is that there is less switching loss.
It should be apparent that the more times you have to switch the current the higher the total loss.
The upper limit would likely be due to switching and other parasitic losses, long before you reach any LED limitations at those currents.
It is definitely not apparent to me why there are losses when one PWMs an LED. So I did my homework before posting, and found several interesting sources of info. The file attached is the one I found to be most useful at explaining things a bit.
I found this paragraph rather interesting:
For the diode to transition from the conducting to the non-conducting state, the charge distribution must change. This can only happen with a movement of charge, which is a flow of current. In some cases, such as a silicon carbide diode, the charge distribution difference is caused solely by the junction capacitance: again a movement of charge occurs when moving from the conducting to the non-conducting state.
So it seems that yes, the diode's capacitance is partly responsible for these losses, but the problem is not as simple as it seems (at least to me). It also seems that the diode's reverse recovery current plays a role, but also what the diode is being switched with:
The important conclusion is that the use of a soft recovery diode will in troduce more switch-on losses
in the diode itself, but save additional losses in the semiconductor switch. When evaluating the performance of a new diode, it is therefore necessary to look at both the diode and semiconductor switch performance, not just the diode performance.
That last observation makes it understanding it even more complicated for me... Is there a simpler way of explaining it? Or is this as simple as it gets?
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