Hi,
I have got following question:
How many sides does a polygon have if the measure of each interior angle is 8 times the measure of each exterior angle?
The formula to find measurement of each interior angle of a polygon is:
((n-2) * 180)/n and the formula to find the measurement of each exterior angle is:
360/n
Now ((n-2) * 180)/n = 8 * (360)/n
now ((n-2) * 180) = 8 * 360
180 n -360 = 8 * 360
180 n = 7 * 360
n = 14
I am getting n = 14 which is wrong.
Some body please guide me what's the prob with it.
Zulfi.
I have got following question:
How many sides does a polygon have if the measure of each interior angle is 8 times the measure of each exterior angle?
The formula to find measurement of each interior angle of a polygon is:
((n-2) * 180)/n and the formula to find the measurement of each exterior angle is:
360/n
Now ((n-2) * 180)/n = 8 * (360)/n
now ((n-2) * 180) = 8 * 360
180 n -360 = 8 * 360
180 n = 7 * 360
n = 14
I am getting n = 14 which is wrong.
Some body please guide me what's the prob with it.
Zulfi.