Infrared LED filter

Thread Starter

Tejasvi471

Joined Jun 9, 2020
35
Please tell us what you are trying to do. You seem to have had very little experience with spectroscopy and in particular infrared. I do not have time to go through every word with you.
Yes you are correct I am novice, I don't have experience in anything.

I have redrawn simple form of my model for better understanding of members, hope it helps.

Please note these shutters are mechanically operated.
I have removed optical link with open air
These filters are drawn in Lens shape but they are not really Lens.

I am open to suggestion
 

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Alec_t

Joined Sep 17, 2013
15,119
If i read it correctly it passes band of wavelength 24 nm wide with wavelength peak at 2.3 µm
My understanding is that it passes a band centred on 2.3um (uncertainty12nm) with a bandwidth (measured to the half peak height) of 50nm (uncertainty10nm).
And yes, it's expensive: which is probably why modulation has been suggested above as a more viable option.
 

jpanhalt

Joined Jan 18, 2008
11,087
spec of FB2300-50
1. CENTER WAVELENGTH (CWL): 2.30 µm ± 12 nm
2. FULL WIDTH HALF MAXIMUM (FWHM): 50 ± 10 nm
If i read it correctly it passes band of wavelength 24 nm wide with wavelength peak at 2.3 µm

On another note they are really pricey $331
Do you understand the difference between um and nm? A wavelength of 2.3 um is at the beginning of what is considered the "finger print" region of the infrared spectrum.

1593554408343.png

That is not what you want according to your original post.
 

Thread Starter

Tejasvi471

Joined Jun 9, 2020
35
Do you understand the difference between um and nm? A wavelength of 2.3 um is at the beginning of what is considered the "finger print" region of the infrared spectrum.

View attachment 211103

That is not what you want according to your original post.
Yes I understand, 2.3 um can not be detected by PT333-3C as its Rang of Spectral Bandwidth is λ0.5 --- 400-1100 --- nm

I was just trying to clarify.
 
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