hi 123,
This is a LTSpice sim of your circuit, with minor modifications.
E
This is a LTSpice sim of your circuit, with minor modifications.
E
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This is a fairly easy to follow schematic, but we have no idea what the flipflops are or what signals they use. AND with the data and enable inputs open there is no way the circuit can function.I tried to make a quiz game show circuit thingy, like the ones in Jeopardy, to have a game night with my family. My circuit doesn't work as there are 2 leds lighted up instead of 1. Other than adding a pull up to each d flip flop what else could i do? Also anyone know how to make it such that there is a certain amount of time before they cant answer anymore or like a certain sound for a wrong and correct answer.
View attachment 212500
View attachment 212503
chips?Hello,
@ericgibbs , As I see the IO1 is the 5 Volts from the supply.
See the right side at the supply.
The only thing that worries me is that all labels are as output.
@electronics123 , Wich chips are you actualy using?
That way we can see wich pins need to be grounded or out high.
Bertus
rookie mistake haha, the flip flops are cd4013sThis is a fairly easy to follow schematic, but we have no idea what the flipflops are or what signals they use. AND with the data and enable inputs open there is no way the circuit can function.
Get two MC14013, or CD4013 FFs and use them, but with all of the unused inputs tied to common and it should work.
And you do not want inverted Qbar (Q_) outputs on a FF. Not ever.
wow this is really helpful thanks! will try to implement ithi 123,
This is a LTSpice sim of your circuit, with minor modifications.
E
OK, no mention of the type and no way to know. And there is NEVER an inverted sign on the Q-bar output, that is confusing.rookie mistake haha, the flip flops are cd4013s
The chips are the IC's that you are using.chips?
Basically correct.Brilliant circuit, Crutschow.
The way I understand it works, the first SCR that gets triggered will clamp down the voltage at node "A" low enough such that the remaining SCRs do no have a way to provide a sufficient holding current?
This is the classic game show circuit! Nice presentation @crutschowBasically correct.
The first SCR that fires pulls the node "A" voltage below the D3 Zener voltage ("A" voltage equal to the LED + SCR forward current drop), so there's then no longer voltage at node "T" to fire any of the other SCRs.
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