Hello! I need help simplifying this electrical diagram. Thank you!
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Hello! I need help simplifying this electrical diagram. Thank you!
You just gave the answer away. How could it have been anything but Rab.Hello again,
One thing i forgot to mention.
I dont see any resistor values given in the first post. For example, 10 Ohms, 100 Ohms 1.2k, etc. I only see the resistor labels R1, R2, R3, R4, etc.
If there are no values given this becomes a symbolic calculation which will involve every resistor in the network, and because they are connected together in a somewhat complex way, the resulting symbolic expression will be very complicated with a lot of characters even when factored and simplified. This means you probably have to use a math program that can handle symbolic algebra.
An alternate way however is to just keep lumping resistor combinations as you go, and renaming those lumped combinations with a new 'R' number.
For an example unrelated directly to the network in the first post, say we have R1 and R2 in series and then we have to put that set in parallel to R3. This would come out to (factored on way):
RT=((R2+R1)*R3)/(R3+R2+R1)
and now say we have another resistor R4 in series with that. The total would come out to:
RT=((R3+R2+R1)*R4+(R2+R1)*R3)/(R3+R2+R1)
when factored one way. This means every time we involve another resistor the final expression becomes more and more complex.
If instead we lumped the first calculation with R1, R2, and R3 we could define:
Ra=((R2+R1)*R3)/(R3+R2+R1)
and now when we add R4 we get:
RT=Ra+R4
a much simpler expression.
You do have to show all your definitions though or else nobody would know what Ra is and so the above would not really be a solution.
For the problem in the first post you would end up with several definitions:
Ra=...
Rb=...
Rc=...
.
.
Rn=...
then
RT=...
Homework was assigned on Friday  he/she will be back the evening before it's due.One wonders where the thread starter is.
You can not state one value to solve this symbolically. That's because if you do state one value, you MUST include all the definitions that trickle back to every single resistor in the circuit. In other words, you also have to show the derivation of each lumped value.You just gave the answer away. How could it have been anything but Rab.
Hi,For example, you can
View attachment 262605
Hi,R_AB = V_AB / I1 ≈ 123.8185 V / 1 A ≈ 123.8185 Ω
View attachment 262870
You mean this:In post #1:
R_n+1 = R_n + 5 Ω
R4 = 37 Ω
View attachment 262877View attachment 262895
So answer is 123.45 Ω
I always tune monitors to see full gamma of hues.How did you see that text in the drawing? It shows up on my monitor as a big black box.
Your image does too.
I had to pull the text in my image above out of the shadows
The image in the first post is probably the worst image i have ever seen on this forum to date.
Can you see the text in my image above or is it too light on your monitor?
Oh ok thanks, i even had trouble seeing it when i turned my brightness up.I always tune monitors to see full gamma of hues.
I see TS's image and your light variant of image very well.
My monitor has brightness 30% and contrast 50%.
Definitely, you can solwing your last problem by the same way:
by Robert Keim
by Aaron Carman
by Robert Keim