i have an inverter with an input voltage of 12v 100 ah , and i have two batteries with voltage of 12v 100 ah. if i parallel connect , the output voltage with Ah will be 12v 200ah, how i reduce amperage to 100ah

Can anybody please help...

 

Well, amp is the result of voltage and resistance:
V = IR
So re-arrange and you get I = V/R
You want less current drawn? Use a resistor but that would dissapate power in the form of heat.

 

I am worried about your question. I don't think you quite understand Volts (V), Amps (A) or Ampere Hours (Ah).

A battery may have a terminal voltage of 12V. It may have an energy capacity of 100Ah. This means it could deliver 100A for 1 hour or 1A for 100 hours.

Put two of these batteries in parallel. The voltage is still 12V. But the amount of energy is doubled.

Your inverter will draw an amount of amps depending on the work it is doing, not on what the battery configuration is.

Sometimes easier to think a fluid like water or air.
Example: An air compressor with a 20 litre tank pumped up to 6 bar.
The pressure is equivalent to the voltage. The 20 litre volume is equivalent to the Ah. The current A is equivalent to the amount of air (litres/min) flowing out through the air line driving a tool (say).

Hope that makes it clearer!

 

This is why I wrote, "Ohm's Law for Noobies". Top of the Chat page.

http://forum.allaboutcircuits.com/showthread.php?t=69757