How to activate a relay with resistance.

Thread Starter

jerlam01

Joined May 16, 2023
4
Hey guys, nubey here, or more nubey than I want to be. I need help on a project where I'm looking to activate a relay when resistance is within a certain range. Is there anything out there I can buy? I looked in all the normal places but can't find anything. Resistance can't be a wide range and will need to be around 6k. Thanks for the help...
 

MrChips

Joined Oct 2, 2009
34,629
Sure can do.
Use the resistor in a voltage divider configuration (or bridge circuit) and apply the voltage difference to an analog comparator.

1684266004224.png
 

MisterBill2

Joined Jan 23, 2018
27,187
There is a circuit that is easily adapted to monitor a resistance. It is called a "window comparator. You will need to provide asupply to pass a current through the resistance so that you have a voltage to be monitored. It is cheap and easy to build and use. I am sure that such modules are available, the circuit is published in many places. But I would not look for it on yoo toob.
 

Thread Starter

jerlam01

Joined May 16, 2023
4
What is generating this resistance and what is its range?
I have a resistor in an ice maker that I want to cycle the ice when it reaches 20K ohms. When warm water enters the ice maker the resistance goes down to 5k and as it cools down and freezes the resistance climbs. At 20k ohms I want it to close a relay.
 

AnalogKid

Joined Aug 1, 2013
12,049
It sounds like you have a thermistor, not a simple resistor. What is the power source you have available for a module or circuit?

So, you have a thermistor, and you want a relay to close when the resistance increases above 20 K, and open when the resistance decreases below 5 K. Correct?

If yes, this seems backwards. Wouldn't you want the relay to open (remove power) when things are cold enough?

Separate from that, there are a ton of mechanical and electronic thermostat devices / parts / modules on ebay.

ak
 

Thread Starter

jerlam01

Joined May 16, 2023
4
It sounds like you have a thermistor, not a simple resistor. What is the power source you have available for a module or circuit?

So, you have a thermistor, and you want a relay to close when the resistance increases above 20 K, and open when the resistance decreases below 5 K. Correct?

If yes, this seems backwards. Wouldn't you want the relay to open (remove power) when things are cold enough?

Separate from that, there are a ton of mechanical and electronic thermostat devices / parts / modules on ebay.

ak
You are correct, what i meant is thermistor. Not sure why Im saying resistor. I need to apply power at 20k using a reversable polarity timed relay. anything under 15k would work to turn it off again.
 

MrChips

Joined Oct 2, 2009
34,629
Copied from post #3.

1684340694462.png

R3 + Rsensor constitute a voltage divider.

If the excitation voltage is 12V, for example, setting R3 = Rsensor = 20kΩ will give 6V at the junction.

R1 + R2 is your reference voltage divider.
If R1 = 20kΩ and R2 = 15kΩ, your reference voltage is 12V x 15k/35k = 5.14V

Thus what you need is a window comparator (using two comparators). Or use a single comparator with hysteresis.

When Vout exceeds (6 - 5.14)V = 0.86V the relay must turn on.
When Vout falls below 0V the relay turns off.

Adjust the values of R1, R2, and R3 to give you suitable switching thresholds.
 

Dodgydave

Joined Jun 22, 2012
11,395
You are correct, what i meant is thermistor. Not sure why Im saying resistor. I need to apply power at 20k using a reversable polarity timed relay. anything under 15k would work to turn it off again.
That's a NTC thermistor , so a simple comparator circuit will work with a LM311 op amp.
 

MisterBill2

Joined Jan 23, 2018
27,187
I suggested a "window comparator in post #5. There may be an assembled one available as a module someplace. Having the name of the device makes the search easier.
 
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