Please help me to prove that
X" + ( a^2 )X = 0 where X= Asin(ax) + Bcos(ax)
Cause I got a different expression with an exponential and when I use maclaurin to approximate my expression and the supposed function , I found them to be different .
Help would be greatly appreciated !!!!
X" + ( a^2 )X = 0 where X= Asin(ax) + Bcos(ax)
Cause I got a different expression with an exponential and when I use maclaurin to approximate my expression and the supposed function , I found them to be different .
Help would be greatly appreciated !!!!