Help with Series-Parallel Circuits!

Thread Starter


Joined Oct 10, 2020
Hi, I am a college student, and my professor gave us a quiz that is due tomorrow night. I am having a hard time getting this problem right. any help would be much appreciated. I really want to pass this class. lol.
Thanks in advanced!
(i've attached a picture of the question)



Joined Mar 10, 2019
Hint: Every "triangle" of resistors can be looked as the 2 outside ones as in series, and those 2 series resistors are then in parallel with the third resistor. That then gives you a total resistance between two points of the triangle.

The Electrician

Joined Oct 9, 2007
Using sagor's tip, start at the lower left node labeled "A". Replace the two 1kΩ resistors with a single 2kΩ resistor. Now you have 2kΩ in parallel with 560Ω. This should give you a value of 437.5Ω. The two 1kΩ and the 560Ω resistors can be replaced with a single 437.5Ω resistor. Do the same thing to the right triangle of resistors. Work your way up until you get to the 60 V source and you will have the equivalent resistance applied to the source.

For the voltage across A-B, work the problem backwards.