I ran into a little problem when trying to find the product of 2 decimal places. How to do it correctly? I also need to find the number of decimal places in other factors. Can't understand this topic, maybe someone can explain?

 

Show us an example problem and your best attempt to solve the problem.

 

There are different ways of doing this.
What grade are you in? What methods have you been taught in school?

Here is one method you can used.
Let us give an example using random numbers:

1234.567 x 0.0987

Normalize each number to one decimal in the whole number part.

1234.567 = 1.234567 x 1000 = 1.234567 x 10^3
0.0987 = 9.87 x 0.01 = 9.87 x 10^(-2)

Do the multiplication: 1.234567 x 9.87
Add the exponents: (3) + (-2) = 1

Get an idea of what to expect for an answer by doing the multiplication in your head using estimates. The product will be a value between 1 and 100. It could be 1 and never 100.
e.g. 1.234567 x 9.87 ≅ 1.2 x 10 = 12

Apply the exponent:
The approximate answer is 12 x 10^1 = 120

Now you can do the correct multiplication and then apply the exponent:
1.234567 x 9.87 x 10^1 = 12.185176 x 10 = 121.85176

 

There are different ways of doing this.
What grade are you in? What methods have you been taught in school?

Here is one method you can used.
Let us give an example using random numbers:

1234.567 x 0.0987

Normalize each number to one decimal in the whole number part.

1234.567 = 1.234567 x 1000 = 1.234567 x 10^3
0.0987 = 9.87 x 0.01 = 9.87 x 10^(-2)

Do the multiplication: 1.234567 x 9.87
Add the exponents: (3) + (-2) = 1

Get an idea of what to expect for an answer by doing the multiplication in your head using estimates. The product will be a value between 1 and 100. It could be 1 and never 100.
e.g. 1.234567 x 9.87 ≅ 1.2 x 10 = 12

Apply the exponent:
The approximate answer is 12 x 10^1 = 120

Now you can do the correct multiplication and then apply the exponent:
1.234567 x 9.87 x 10^1 = 12.185176 x 10 = 121.85176

Thanks, that should help me. I'll try today

 

There are different ways of doing this.
What grade are you in? What methods have you been taught in school?

Here is one method you can used.
Let us give an example using random numbers:

1234.567 x 0.0987

Normalize each number to one decimal in the whole number part.

1234.567 = 1.234567 x 1000 = 1.234567 x 10^3
0.0987 = 9.87 x 0.01 = 9.87 x 10^(-2)

Do the multiplication: 1.234567 x 9.87
Add the exponents: (3) + (-2) = 1

Get an idea of what to expect for an answer by doing the multiplication in your head using estimates. The product will be a value between 1 and 100. It could be 1 and never 100.
e.g. 1.234567 x 9.87 ≅ 1.2 x 10 = 12

Apply the exponent:
The approximate answer is 12 x 10^1 = 120

Now you can do the correct multiplication and then apply the exponent:
1.234567 x 9.87 x 10^1 = 12.185176 x 10 = 121.85176
I was also able to find on https://plainmath.net/1927/the-product-decimals-062-factors-decimals-many-decimals-other-factors a similar suitable solution for you. It might be useful as well.

Thanks to your decision, I was able to do my homework perfectly, thank you very much!

 

The many times I've run across this thread I ended wondering how someone able to deal with the concept of negative power of a number has difficulty in multiplying decimal numbers of different order.

Anyway, tomorrow in the morning I have a new year to start even if I ignore the answer. So, let it be.

 

The many times I've run across this thread I ended wondering how someone able to deal with the concept of negative power of a number has difficulty in multiplying decimal numbers of different order.

Anyway, tomorrow in the morning I have a new year to start even if I ignore the answer. So, let it be.

Some times it only takes a little spark to ignite a memory and facilitate the ability to solve a problem. I've seen it happen with young students and my aging parents. When it starts happening to me, I'll get my affairs in order snd clean up my bench and sell my vintage parts inventory.