in lecture last week, our instructor gave us an extra credit problem that we had no clue how to solve. i have gotten most of the wye diagram done, and am confused on what to do with the angle at the end.
heres the problem...
A balanced three phase load consisting of 4+j3 ohms per pahse is connected to a 208Y/120V source. Calculate the (1)current per phase, (2)power per phase, and (3)total three phase power for the wye connected load. Repeat for a delta connected load.
for the wye diagram, i got
Ian=41.6A at -36.87 degrees
Ibn=41.6A at -156.87 degrees
Icn=41.6A at 83.13 degrees
Pan=8.65kW at -36.87 degrees
Pbn=8.65kW at 96.87 degrees
Pcn=8.65kW at -23.13 degrees
how do i solve for Ptot? would it be 25.95kW+jQ? and what goes in the place of j and Q?
heres the problem...
A balanced three phase load consisting of 4+j3 ohms per pahse is connected to a 208Y/120V source. Calculate the (1)current per phase, (2)power per phase, and (3)total three phase power for the wye connected load. Repeat for a delta connected load.
for the wye diagram, i got
Ian=41.6A at -36.87 degrees
Ibn=41.6A at -156.87 degrees
Icn=41.6A at 83.13 degrees
Pan=8.65kW at -36.87 degrees
Pbn=8.65kW at 96.87 degrees
Pcn=8.65kW at -23.13 degrees
how do i solve for Ptot? would it be 25.95kW+jQ? and what goes in the place of j and Q?