Hi,
I need to find the Norton current of the attached circuit.
Here's what I've done:
First, I transformed the voltage source into a 9 A current source, with the 20 ohm resistor in parallel.
Using the current divider formula, we have 6 A going through that resistor.
Therefore, Isc = 3+3 = 6 A.
I input 6000 into Moodle (mA required) but it says the answer is wrong.
What am I doing wrong?
Thanks.
I need to find the Norton current of the attached circuit.
Here's what I've done:
First, I transformed the voltage source into a 9 A current source, with the 20 ohm resistor in parallel.
Using the current divider formula, we have 6 A going through that resistor.
Therefore, Isc = 3+3 = 6 A.
I input 6000 into Moodle (mA required) but it says the answer is wrong.
What am I doing wrong?
Thanks.
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