Remove R2 and you'll see two parallel sets of 6 ohms (3 + 3) in parallel. If you have two resistors (6 ohms each), I can assure you that the equivalent resistance is NOT 6 ohms for the full circuit.Kindly explain how to solve the following network. The answer is 6 ohms and independent of R2. Can anyone explain that?
Thanks for the reply. Yes, I just misquoted it. The answer is 3 ohms. Really sorry for that. But can you explain how do we arrive at 3 ohms.Remove R2 and you'll see two parallel sets of 6 ohms (3 + 3) in parallel. If you have two resistors (6 ohms each), I can assure you that the equivalent resistance is NOT 6 ohms for the full circuit.
Yes, I am 100% clear. Thanks.As I gave you the hint before, the 400Ω resistor has no current. Therefore no voltage. No voltage, no current no apparent resistance. In other words the 400Ω resistor is just a goldbrick circuit. It does nothing to the values.
SO: You have two 3Ω resistors in series - effectively creating a 6Ω resistor. You have a second set of resistors constituting another 6Ω resistor. Two 6Ω resistors in parallel equate to 3Ω. Do you understand how we come up with 3Ω?
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