# Fault Analysis using Symmetrical Components.

Discussion in 'General Electronics Chat' started by lam58, Aug 7, 2015.

1. ### lam58 Thread Starter Member

Jan 3, 2014
69
0
Hi could someone check my answer to the question below. THIS IS NOT HOMEWORK.

Question:

$I_{fA} = 3I_{1A} = 3I_{2A} = 3I_{0A} \Rightarrow I_{fA} = \frac{3E}{Z_1 + Z_2 + Z_0} = \frac{33kV}{20+20+30} = 471.43A$
Then using the same method I got $I_{fB} = 942.86A$