I have the diagram attached for a small signal model of a differential amplifier that my professor gave me. I am having a little trouble understanding where he got the expression for the current ib2.
According to his notes, it says that when source e2 is 0 V (that is, shorted to ground), the expression for the current is
\(i_{b2} = \frac{-e_1}{2 \times h_{ie}}\)
I've been staring at this for a while now trying to understand his logic and am stumped. How did he get this expression? What loop do you have to go through? Thanks in advance for any help.
According to his notes, it says that when source e2 is 0 V (that is, shorted to ground), the expression for the current is
\(i_{b2} = \frac{-e_1}{2 \times h_{ie}}\)
I've been staring at this for a while now trying to understand his logic and am stumped. How did he get this expression? What loop do you have to go through? Thanks in advance for any help.
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