First i calculated the current at v0=8v by doing 8v/10k(ohms) which equals to 0.8mAShow us how you went about calculating Rx so we can see where you went wrong. I can see a voltage and a current that you can calculate very easily.
Les.
Hello,
The voltage accross R1 is not the mentioned 1.6 Volts.
The powersource is 10 Volts.
Accross R2 the voltage is 8 Volts.
What is the voltage accross R2?
Bertus
PS I moved your thread from digital design to homework help.
Because the voltage across R1 plus the voltage across R2 must add up to the supply voltage.ok thanks ill make sure to post in homework help next time.
i found that he voltage is 1.6 volts at R1 why is it wrong?
i didnt undertstand what you said after that im sorry.
oh i see so my finding 1.6v but its just simply 2v because thats the voltage difference.Hello,
On one side of the resistor R1 there is the powersource of 10 Volts.
On the other side of the resistor R1 there is resistor R2 with a voltage of 8 Volts.
What is the voltage difference accross R1?
Bertus
You are making one of the classic mistakes in applying Ohm's Law.First i calculated the current at v0=8v by doing 8v/10k(ohms) which equals to 0.8mA
then i calculated the voltage over R1 by doing 0.8mA x 2k(ohms) which equals to 1.6v
i know that since Rx and R2 are parallel they have the same voltage which is 8v
so all i need to do is find the current through Rx so then i can divide it by 8V and get Rx.
right?
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