Why is the average voltage Eav = Emax* 2 /Pie,
My understanding is 2*Emax = Peak to Peak voltage
therefore the E average Eav= 2Emax / 2 pie R,
R,radius should also equal to E av,
Therefore E av = 2 Emax / 2 pie Eav
Therefore (Eav= sq. rt of Emax /pie)
My understanding is 2*Emax = Peak to Peak voltage
therefore the E average Eav= 2Emax / 2 pie R,
R,radius should also equal to E av,
Therefore E av = 2 Emax / 2 pie Eav
Therefore (Eav= sq. rt of Emax /pie)